birthday mod - sql sorteren

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Danko
Berichten: 109
Lid geworden op: 02 dec 2003, 19:56
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birthday mod - sql sorteren

Bericht door Danko » 19 apr 2005, 16:59

Code: Selecteer alles

// Birthday Mod, Show users with birthday 
$sql = ($board_config['birthday_check_day']) ? "SELECT user_id, username, user_birthday,user_level FROM " . USERS_TABLE. " WHERE user_birthday!=999999 ORDER BY username" :"";
if($result = $db->sql_query($sql)) 
{ 
	if (!empty($result)) 
	{ 
		$time_now = time();
		$this_year = create_date('Y', $time_now, $board_config['board_timezone']);
		$date_today = create_date('Ymd', $time_now, $board_config['board_timezone']);
		$date_forward = create_date('Ymd', $time_now+($board_config['birthday_check_day']*86400), $board_config['board_timezone']);
	      while ($birthdayrow = $db->sql_fetchrow($result))
		{ 
		      $user_birthday2 = $this_year.($user_birthday = realdate("md",$birthdayrow['user_birthday'] )); 
      		if ( $user_birthday2 < $date_today ) $user_birthday2 += 10000;
			if ( $user_birthday2 > $date_today  && $user_birthday2 <= $date_forward ) 
			{ 
				// user are having birthday within the next days
				$user_age = ( $this_year.$user_birthday < $date_today ) ? $this_year - realdate ('Y',$birthdayrow['user_birthday'])+1 : $this_year- realdate ('Y',$birthdayrow['user_birthday']); 
				switch ($birthdayrow['user_level'])
				{
					case ADMIN :
		      			$birthdayrow['username'] = '<b>' . $birthdayrow['username'] . '</b>'; 
      					$style_color = 'style="color:#' . $theme['fontcolor3'] . '"';
						break;
					case MOD :
		      			$birthdayrow['username'] = '<b>' . $birthdayrow['username'] . '</b>'; 
      					$style_color = 'style="color:#' . $theme['fontcolor2'] . '"';
						break;
					default: $style_color = '';
				}
				$birthday_week_list .= ' <a href="' . append_sid("profile.$phpEx?mode=viewprofile&" . POST_USERS_URL . "=" . $birthdayrow['user_id']) . '"' . $style_color .'>' . $birthdayrow['username'] . ' ('.$user_age.')</a>,'; 
			} else if ( $user_birthday2 == $date_today ) 
      		{ 
				//user have birthday today 
				$user_age = $this_year - realdate ( 'Y',$birthdayrow['user_birthday'] ); 
				switch ($birthdayrow['user_level'])
				{
					case ADMIN :
		      			$birthdayrow['username'] = '<b>' . $birthdayrow['username'] . '</b>'; 
      					$style_color = 'style="color:#' . $theme['fontcolor3'] . '"';
						break;
					case MOD :
			      		$birthdayrow['username'] = '<b>' . $birthdayrow['username'] . '</b>'; 
      					$style_color = 'style="color:#' . $theme['fontcolor2'] . '"';
						break;
					default: $style_color = '';
				}

				$birthday_today_list .= ' <a href="' . append_sid("profile.$phpEx?mode=viewprofile&" . POST_USERS_URL . "=" . $birthdayrow['user_id']) . '"' . $style_color .'>' . $birthdayrow['username'] . ' ('.$user_age.')</a>,'; 
		      }
			 
		}
		if ($birthday_today_list) $birthday_today_list[ strlen( $birthday_today_list)-1] = ' ';
		if ($birthday_week_list) $birthday_week_list[ strlen( $birthday_week_list)-1] = ' ';
	} 
	$db->sql_freeresult($result);
}
de jarige gebruikers worden nu gesorteerd op de username, ik wil deze laten sorteren op de datum dat ze jarig zijn. sorteren op user_birthday werkt natuurlijk niet want dat zit het geboortejaar erbij
ik moet dus iets krijgen met user_birthday/$leeftijd

hoe kan ik dit het makkelijkste doen?

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