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berichten van een bepaald fora laten zien *edit

Geplaatst: 08 feb 2007, 19:47
door roelor
Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in C:\Program Files\xampp\htdocs\roelor\laatsteposts.php on line 12
WAAROM!!

Code: Selecteer alles

<? include_once ("forum/config.php");
   $mysql_connection = mysql_connect ($dbhost, $dbuser, $dbpasswd) or die ("Connection failed");
   mysql_select_db ($dbname) or die ("Selecting database failed");
       
	    $id = 2;
$result = mysql_query("SELECT * FROM test WHERE id=$id",$db);
   $query = "SELECT * FROM php2b_topics WHERE forum_id=$id
   ";
   $res   = mysql_query($query);
   while($data = @mysql_fetch_array($res))
   {
    echo "&nbsp;<a href=\"forum/viewtopic.php?t=".$data["topic_id"]."\">".$data['topic_title']."</a><br>";
   }
 



?>

Geplaatst: 08 feb 2007, 20:21
door roelor
oh laatmaar